Download free pdf of Chapter 8 Comparing Quantities Worksheets for Class 7 Maths with answers. Students can easily get all the Class 7 Maths Worksheets and Exercises in Free Printable ( PDF Format) as per the latest syllabus and examination pattern in CBSE and NCERT pattern. Below you will find all the Comparing Quantities related sums that are asked in 7th Grade Mathematics Exams Across Indian Schools.
Comparing Quantities Worksheets for Class 7 in PDF Format
- Class 7 Comparing Quantities Worksheet with Answers – 8
- Class 7 Comparing Quantities Worksheet with Answers – 7
- Class 7 Comparing Quantities Worksheet with Answers – 6
- Class 7 Comparing Quantities Worksheet with Answers – 5
- Class 7 Comparing Quantities Worksheet with Answers – 4
- Class 7 Comparing Quantities Worksheet with Answers – 3
- Class 7 Comparing Quantities Worksheet with Answers – 2
- Class 7 Comparing Quantities Worksheet with Answers – 1
- MCQ Questions for Class 7 Maths Chapter 8 Comparing Quantities
- MCQ Comparing Quantities Chapter 8 Class 7 Maths
CBSE Class 7 Comparing Quantities Worksheet with answers
Q.1) Find: (a) 50% of 164 (b) 75% of 12
Answer:
(a) 50% of 164 = (50/100) * 164 = 0.5 * 164 = 82
(b) 75% of 12 = (75/100) * 12 = 0.75 * 12 = 9
Q.2) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now?
a) Rs 40800 b) Rs 32300 c) Rs 40000 d) none of these
Answer:
Original price = Rs 34,000
Price increase = 20% of Rs 34,000 = (20/100) * 34,000 = Rs 6,800
New price = Original price + Price increase = Rs 34,000 + Rs 6,800 = Rs 40,800
So, the price of the scooter now is Rs 40,800 (option a).
Q.3) The price of a scooter was Rs 34,000 last year. It has decreased by 5% this year. What is the price now?
a) Rs 40800 b) Rs 32300 c) Rs 40000 d) none of these
Answer:
Original price = Rs 34,000
Price decrease = 5% of Rs 34,000 = (5/100) * 34,000 = Rs 1,700
New price = Original price – Price decrease = Rs 34,000 – Rs 1,700 = Rs 32,300
So, the price of the scooter now is Rs 32,300 (option b).
Q.4) A sum amounts to Rs. 3720 in 8 months at 5% per annum simple interest. The sum is
a) Rs 3500 b) Rs 3600 c) Rs 3560 d) Rs. 3620
Answer:
The sum is:
Let the principal sum be P.
Simple Interest (SI) = P * Rate * Time / 100
3720 = P * 5 * (8/12) / 100
3720 = P * 5 * 2/3 / 100
3720 = (10P/3) / 100
Now, solve for P:
P = (3720 * 100 * 3) / (10 * 2)
P = 111600 / 20
P = Rs 5580
So, the sum is Rs 5580 (option b).
Q.5) At what rate percent per annum simple interest will a sum be double itself in 8 years?
a) 15% b) 14% c) 16% d) 12 .5%
Answer:
Let the rate be R%.
Using the formula for simple interest:
2P = P * R * 8 / 100
Now, solve for R:
2 = R * 8 / 100
2 = R * 0.08
R = 2 / 0.08
R = 25
So, the rate of interest is 25% (option a).
Q.6) At simple interest a sum becomes of itself in 5 years. The rate of interest percent per annum is
a) 8% b) 5% c) 10% d) 12.5%
Answer:
Let the rate be R%.
Using the formula for simple interest:
2P = P * R * 5 / 100
Now, solve for R:
2 = R * 5 / 100
2 = R * 0.05
R = 2 / 0.05
R = 40
So, the rate of interest is 40% (option d).
Q.7) The car that I own can go 150 km with 25 litres of petrol. How far can it go with 30 litres of petrol?
Answer:
To find how far it can go with 30 litres of petrol, you can set up a proportion:
(150 km / 25 litres) = (x km / 30 litres)
Cross-multiply:
150 * 30 = 25 * x
4500 = 25 * x
Now, solve for x:
x = 4500 / 25
x = 180 km
The car can go 180 km with 30 litres of petrol.
Q.8) In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?
Answer:
To find how many computers will be needed for 24 students, you can set up a proportion:
(3 computers / 6 students) = (x computers / 24 students)
Cross-multiply:
3 * 24 = 6 * x
72 = 6 * x
Now, solve for x:
x = 72 / 6
x = 12
So, 12 computers will be needed for 24 students.
Q.9) Mala has a collection of bangles. She has 20 gold bangles and 10 silver bangles. What is the percentage of bangles of each type? Put it in the tabular form?
Answer:
To find the percentage of bangles of each type, you can put it in a tabular form:
| Type of Bangles | Number of Bangles | Percentage |
|---|---|---|
| Gold | 20 | ? |
| Silver | 10 | ? |
To calculate the percentage for each type, use the formula: Percentage = (Number of Bangles of that type / Total Number of Bangles) * 100
For Gold bangles: Percentage = (20 / (20 + 10)) * 100 = (20 / 30) * 100 = (2/3) * 100 = 66.67%
For Silver bangles: Percentage = (10 / (20 + 10)) * 100 = (10 / 30) * 100 = (1/3) * 100 = 33.33%
So, Mala has approximately 66.67% gold bangles and 33.33% silver bangles.
Q.10) Out of 25 children in a class, 15 are girls. What is the percentage of girls?
Answer:
To find the percentage of girls, use the formula: Percentage = (Number of Girls / Total Number of Children) * 100
Percentage = (15 / 25) * 100 = (3/5) * 100 = 60%
So, the percentage of girls in the class is 60%.
Q.11) Convert the given decimals to per cents: (a) 0.75 (b) 0.09 (c) 0.2
Answer:
(a) 0.75 = 75% (b) 0.09 = 9% (c) 0.2 = 20%
Q.12) Out of 32 students, 8 are absent. What percent of the students are absent?
Answer:
To find the percent of students absent, use the formula: Percentage = (Number of Absent Students / Total Number of Students) * 100
Percentage = (8 / 32) * 100 = (1/4) * 100 = 25%
So, 25% of the students are absent.
Q.13) There are 25 radios, 16 of them are out of order. What percent of radios are out of order?
Answer:
To find the percent of radios out of order, use the formula: Percentage = (Number of Radios Out of Order / Total Number of Radios) * 100
Percentage = (16 / 25) * 100 = (64/100) * 100 = 64%
So, 64% of the radios are out of order.
Q.14) A shop has 500 parts, out of which 5 are defective. What percent are defective?
Answer:
Percentage = (Number of Defective Parts / Total Number of Parts) * 100
Percentage = (5 / 500) * 100 = (1/100) * 100 = 1%
So, 1% of the parts are defective.
Q.15) There are 120 voters, 90 of them voted yes. What percent voted yes?
Answer:
Percentage = (Number of Votes for “Yes” / Total Number of Voters) * 100
Percentage = (90 / 120) * 100 = (3/4) * 100 = 75%
So, 75% of the voters voted yes.
Q.16) If 65% of students in a class have a bicycle, what percent of the student do not have bicycles?
Answer:
To find the percent of students who do not have bicycles, subtract 65% from 100% (since 100% represents all the students):
Percentage without bicycles = 100% – 65% = 35%
So, 35% of the students do not have bicycles.
Q.17) We have a basket full of apples, oranges and mangoes. If 50% are apples, 30% are oranges, then what percent are mangoes?
Answer:
To find the percent of mangoes, subtract the percentages of apples and oranges from 100% (since 100% represents all the fruits):
Percentage of mangoes = 100% – 50% – 30% = 20%
So, 20% of the fruits are mangoes.
Q.18) A survey of 40 children showed that 25% liked playing football. How many children liked playing football?
Answer :
To find the number of children who liked playing football, use the formula: Number of children = (Percentage who liked football / 100) * Total number of children
Number of children = (25% / 100) * 40 = (1/4) * 40 = 10
So, 10 children liked playing football.
Q.19) In what time will Rs. 1600 amount to Rs. 1768 at 6% per annum simple interest?
Answer:
Use the formula for simple interest: Simple Interest (SI) = (Principal * Rate * Time) / 100
Given: Principal (P) = Rs. 1600, Amount (A) = Rs. 1768, Rate (R) = 6%
We need to find Time (T): SI = A – P SI = Rs. 1768 – Rs. 1600 = Rs. 168
Now, plug in the values and solve for Time (T): 168 = (1600 * 6 * T) / 100
Simplify the equation: 168 = (96T)
Now, solve for T: T = 168 / 96 T = 7 / 4 T = 1.75 years
So, it will take 1.75 years for Rs. 1600 to amount to Rs. 1768 at 6% per annum simple interest.
Q.20) At what rate percent per annum simple interest will a sum be double itself in 8 years?
Answer:
Let the rate be R%. Using the formula for simple interest: 2P = P * R * 8 / 100
Now, solve for R: 2 = R * 8 / 100 2 = R * 0.08
R = 2 / 0.08 R = 25
So, the rate of interest is 25% per annum.
Q.21) At what rate percent per annum simple interest will a sum treble itself in 16 years?
Answer :
Let the rate be R%. Using the formula for simple interest: 3P = P * R * 16 / 100
Now, solve for R: 3 = R * 16 / 100 3 = R * 0.16
R = 3 / 0.16 R = 18.75
So, the rate of interest is 18.75% per annum.
Q.22) A sum amounts to Rs. 3720 in 8 months at 5% per annum simple interest. Find the sum.
Answer :
Use the formula for simple interest: Simple Interest (SI) = (Principal * Rate * Time) / 100
Given: SI = Rs. 3720, Rate (R) = 5%, Time (T) = 8 months
We need to find Principal (P): SI = (P * R * T) / 100 3720 = (P * 5 * 8) / 100
Now, solve for P: 3720 = (40P) / 100
Simplify the equation: 3720 = 0.4P
Now, solve for P: P = 3720 / 0.4 P = 9300
So, the principal sum is Rs. 9300.
Q.23) A sum of Rs 10,000 is borrowed at a rate of interest 15% per annum for 2 years. Find the simple interest on this sum and the amount to be paid at the end of 2 years.
Answer:
Use the formula for simple interest: Simple Interest (SI) = (Principal * Rate * Time) / 100
Given: Principal (P) = Rs 10,000, Rate (R) = 15%, Time (T) = 2 years
Calculate SI: SI = (10,000 * 15 * 2) / 100 SI = (30,000) / 100 SI = Rs 300
Now, to find the amount (A) to be paid at the end of 2 years, add the principal and the interest: A = P + SI A = 10,000 + 300 A = Rs 10,300
So, the simple interest is Rs 300, and the amount to be paid at the end of 2 years is Rs 10,300.
Q.24) A man got a 10% increase in his salary. If his new salary is Rs 1,54,000, find his original salary.
Answer:
Let the original salary be X. Increase in salary = 10% of X New salary = X + Increase in salary
Given: New salary = Rs 1,54,000
We need to find X: X + 0.10X = 1,54,000 1.10X = 1,54,000
Now, solve for X: X = 1,54,000 / 1.10 X = Rs 1,40,000
So, his original salary was Rs 1,40,000.
