# Worksheets for Class 7 Lines and Angles – Chapter 5

Download free pdf of Chapter 5 Lines and Angles Worksheets for Class 7 Maths with Answers. Students can easily get all the Class 7 Maths Worksheets and Exercises in Free Printable ( PDF Format) as per the latest syllabus and examination pattern in CBSE and NCERT pattern. Below you will find all the Lines and Angles related sums that are asked in 7th Grade Mathematics Exams Across Indian Schools.

## Lines and Angles Worksheets for Class 7 in PDF Format

### Class 7 Lines and Angles Worksheet with answers

Q.1 ) If two lines intersect at a point, then the vertically opposite angles are always __________________________
(a) equal     (b) unequal    (c) supplementary    (d) complementary

Q2) Two angles forming a linear pair are ________________.
(a) equal    (b) supplementary    (c) unequal    (d) complementary

Q.3) A line that intersects two or more lines at distinct points is called
(a) Parallel    (b) transversal    (c) intersecting    (d) none of these

Q.4) If two adjacent angles are supplementary, then they form _________ .
(a) Corresponding angles    (b) vertically opposite angles
(c) a linear pair of angles    (d) a ray

Answer : (c) a linear pair of angles

Q.5) Identify which of the following pairs of angles are complementary
(a) 65°, 115° (b) 63°, 27° (c) 112°, 68° (d) 130°, 50°

Q.6) Identify which of the following pairs of angles are supplementary.
(a) 80°, 10° (b) 63°, 27° (c) 112°, 68° (d) 45°, 45°

Q.7) Find the angle, which is equal to its complement.
(a) 30°     (b) 25°    (c) 35°    (d) 45°

Q.8) What is the measure of the complement of each of the following angles?
(i) 45° (ii) 65° (iii) 41° (iv) 54°

(i) 45° – Complement: 45°
(ii) 65° – Complement: 25°
(iii) 41° – Complement: 49°
(iv) 54° – Complement: 36°

Q.9) The difference in the measures of two complementary angles is 12°. Find the measures of the angles.

Let one angle be x°.
The other angle (its complement) = 90° – x°
Given: 90° – x° – x° = 12°
Simplify: 90° – 2x° = 12°
Subtract 90° from both sides: -2x° = -78°
Divide by -2: x° = 39°
So, one angle is 39°, and its complement is 51°.

Q.10) What will be the measure of the supplement of each one of the following angles?
(i) 100° (ii) 90° (iii) 55° (iv) 125°

(i) 100° – Supplement: 80°
(ii) 90° – Supplement: 90°
(iii) 55° – Supplement: 125°
(iv) 125° – Supplement: 55°

Q.11) Among two supplementary angles the measure of the larger angle is 44° more than the measure of the smaller. Find their measures.

Q.12) Find the angle which is equal to its complement.

Q.13) Find the angle which is equal to its supplement.

Q.14) Find the measure of an angle which is 240 more than its complement.

Let the angle be x°.
Its complement = 90° – x°
Given: x° = 240° + (90° – x°)
Simplify: x° = 330° – x°
Add x° to both sides: 2x° = 330°
Divide by 2: x° = 165°
So, the angle is 165°.

Q.15) Find the measure of an angle which is 320 less than its complement.

Let the angle be x°.
Its complement = 90° – x°
Given: x° = (90° – x°) – 320°
Simplify: x° = 90° – x° – 320°
Add x° to both sides: 2x° = 90° – 320°
Combine like terms: 2x° = -230°
Divide by 2: x° = -115°
So, the angle is -115°.

Q.16) Find the measure of an angle, if six times its complement is 12° less than twice its supplement.

Let the angle be x°.
Its complement = 90° – x°
Its supplement = 180° – x°
Given: 6(90° – x°) = 2(180° – x°) – 12°
Simplify: 540° – 6x° = 360° – 2x° – 12°
Combine like terms: 540° – 6x° = 348° – 2x°
Add 6x° to both sides: 540° = 348° + 4x°
Subtract 348° from both sides: 4x° = 192°
Divide by 4: x° = 48°
So, the angle is 48°.

Q.17) Identify which of the following pairs of angles are complementary and which are supplementary.
(i) 65°, 115° (ii) 63°, 27° (iii) 112°, 68° (v) 45°, 45° (vi) 80°, 10°

Answer: (i) 65°, 115° – Supplementary