Download free pdf of **Chapter 11 Algebra** **Worksheets for Class 6 Maths with answers**. Students can easily get all the Class 6 Maths Worksheets and Exercises in Free Printable ( PDF Format) as per the latest syllabus and examination pattern in CBSE and NCERT pattern. Below you will find all the Algebra related sums that are asked in 6th Grade Mathematics Exams Across Indian Schools.

## Algebra Worksheets for Class 6 in PDF Format

- Class 6 Maths Worksheet – Algebra
- Class 6 Maths Chapter 11 Algebra Worksheet-6 with Answer
- Class 6 Maths Chapter 11 Algebra Worksheet-5 with Answer
- Class 6 Maths Chapter 11 Algebra Worksheet-4 with Answer
- Class 6 Maths Chapter 11 Algebra Worksheet-3 with Answer
- Class 6 Maths Chapter 11 Algebra Worksheet-2 with Answer
- Class 6 Maths Chapter 11 Algebra Worksheet-1 with Answer
- CBSE Class 6 Maths Worksheet Algebra with Answers
- CBSE Class 6 Maths Worksheet Algebra – 3
- CBSE Class 6 Maths Worksheet Algebra – 2
- CBSE Class 6 Maths Worksheet Algebra – 1
- Class 6 Maths MCQ Worksheet 4 – Algebra
- Class 6 Maths MCQ Worksheet 3 – Algebra
- Class 6 Maths MCQ Worksheet 2 – Algebra
- Class 6 Maths MCQ Worksheet 1 – Algebra

### Class 6 Algebra Worksheet with answers

**Q.1 Which is a solution of the equation 7x + 5 = 19 **(a) x = 2

(b) x = 3

(c) x = 4

(d) x = 6

**Solution** :

7x + 5 = 19

Subtract 5 from both sides:

7x = 19 – 5

7x = 14

Now, divide both sides by 7:

x = 14 / 7

x = 2

So, the **Answer** is (a) x = 2.

**Q.2 Which is a solution of the equation 4x – 3 = 13 **(a) x = 2

(b) x = 3

(c) x = 4

(d) x = 6

**Solution**:

4x – 3 = 13

Add 3 to both sides:

4x = 13 + 3

4x = 16

Now, divide both sides by 4:

x = 16 / 4

x = 4

So, the **Answer** is (c) x = 4.

**Q.3 Which is a solution of the equation 5x + 2 = 17 **(a) x = 2

(b) x = 3

(c) x = 4

(d) x = 6

**Solution**:

5x + 2 = 17

Subtract 2 from both sides:

5x = 17 – 2

5x = 15

Now, divide both sides by 5:

x = 15 / 5

x = 3

So, the **Answer** is (b) x = 3.

**Q.4 Which is a solution of the equation 3x – 14 = 4 **(a) x = 2

(b) x = 3

(c) x = 4

(d) x = 6

**Solution**:

3x – 14 = 4

Add 14 to both sides:

3x = 4 + 14

3x = 18

Now, divide both sides by 3:

x = 18 / 3

x = 6

So, the **Answer** is (d) x = 6.

**Q.5 The age of Siddarth is x years , Sahil is 5 years older than Siddharth therefore Sahils age is **(a) 5x

(b) x–5

(c) x+5

(d) x / 5

**Solution**:

The age of Siddharth is x years, and Sahil is 5 years older than Siddharth. Therefore, Sahil’s age is x + 5 years.

So, the **Answer** is (c) x + 5.

**Q.6 The number of rows is 6 class is equal to the number of columns. If the number of rows is ‘b’ then the total students in the 6 class are: ** (a) 2b

(b) 2 + b

(c) b

^{2}

(d) 0

**Solution**:

The number of rows in the 6th class is ‘b’, and if the number of rows is equal to the number of columns, then the total students in the 6th class are b * b, which is represented as b^{2}.

So, the **Answer** is (c) b^{2}

**Q.7 **The teacher distributes 4 pencils per student. Can you tell how many pencils are needed, given the number of students? (Use *s *for the number of students.)

**Answer:** The number of pencils needed is 4 times the number of students. Therefore, if the number of students is ‘s’, then the number of pencils needed is 4s.

**Q.8** A bird flies 5 kilometer in one minute. Can you express the distance covered by the bird in terms of its flying time in minutes? (Use *t *for flying time in minutes.)

**Answer:** The distance covered by the bird is 5 times its flying time in minutes. Therefore, if the flying time is ‘t’ minutes, then the distance covered is 5t kilometers.

**Q.9 **Vandana is Meghna’s younger sister. Vandana is 4 years younger than Meghna. Can you write Vandana ‘s age in terms of Meghna ‘s age? Take Meghna ‘s age to be *x *years.

**Answer**: Vandana’s age is 4 years younger than Meghna’s age. So, Vandana’s age can be expressed as x – 4 years, where x is Meghna’s age.

**Q.10** Father has brought laddus. He gives some laddus to guests and family members; still 9 laddus remain. If the number of laddus father gave away is *l*, how many laddus did he brought?

**Answer:** Let the number of laddus father brought be L. He gave some laddus to guests and family members, and still, 9 laddus remain. So, the equation can be written as: L – l = 9, where ‘l’ is the number of laddus father gave away.

**Q.11** Apples are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the apples from it fill three smaller boxes and still 20 apples remain outside. If the number of apples in a small box are taken to be *x*, what is the number of apples in the larger box?

**Answer:** Let ‘x’ be the number of apples in the smaller box, and ‘L’ be the number of apples in the larger box. According to the information provided, we have: L = 3x + 20

**Q.12** Radha is drawing a dot Rangoli (a beautiful pattern of lines joining dots with chalk powder. She has 10 dots in a row. How many dots will her Rangoli have for *r *rows? How many dots are there if there are 9 rows? If there are 12 rows?

**Answer:** If Radha has 10 dots in a row and wants to create ‘r’ rows, the total number of dots in her Rangoli will be 10r.

For 9 rows, the number of dots will be 10 x 9 = 90 dots.

For 12 rows, the number of dots will be 10 x 12 = 120 dots

Exercise 1: Basic Algebraic Expressions

**Q.13** Evaluate the expression when x = 4: 3x + 5**Answer**: 3(4) + 5 = 12 + 5 = 17

**Q.14** Simplify the expression: 2x – 7 when x = 6

Answer: 2(6) – 7 = 12 – 7 = 5

**Q.15 **Calculate the value of 5y + 2 when y = 3**Answer**: 5(3) + 2 = 15 + 2 = 17

**Q.16 **Solve for x: 2x + 8 = 20**Answer**: Subtract 8 from both sides: 2x = 20 – 8 = 12

Divide by 2: x = 12 / 2 = 6

**Q.17 **Find the value of y in the equation: 3y – 4 = 11**Answer**: Add 4 to both sides: 3y = 11 + 4 = 15

Divide by 3: y = 15 / 3 = 5

**Q.18 **Solve the equation: 4a + 7 = 23**Answer**: Subtract 7 from both sides: 4a = 23 – 7 = 16

Divide by 4: a = 16 / 4 = 4

**Q.19 **If the cost of a toy is 3x + 10 rupees, and x is 5, what is the cost of the toy?**Answer**: Cost = 3(5) + 10 = 15 + 10 = 25 rupees

**Q.20 **If the length of a rectangle is 2y + 3 centimeters and y is 4, what is the length of the rectangle?**Answer**: Length = 2(4) + 3 = 8 + 3 = 11 centimeters

**Q.21** A number is increased by 8 to get 32. What is the number?**Answer**: Let the number be x.

Equation: x + 8 = 32

Solution for x: x = 32 – 8 = 24

**Q.22** Solve for x: 3x – 5 = 10**Answer**: Add 5 to both sides: 3x = 10 + 5 = 15

Divide by 3: x = 15 / 3 = 5

**Q.23** Find the value of m in the equation: 2m + 6 = 16**Answer**: Subtract 6 from both sides: 2m = 16 – 6 = 10

Divide by 2: m = 10 / 2 = 5

**Q.24 **Solve the equation: 5b + 3 = 18**Answer**: Subtract 3 from both sides: 5b = 18 – 3 = 15

Divide by 5: b = 15 / 5 = 3